Answer
$r = 4, -4$
Work Step by Step
$2r^2-32=0$
$2r^2-32+32=0+32$
$2r^2 = 32$
$2r^2/2 = 32/2$
$r^2=16$
$\sqrt {r^2} = \sqrt {16}$
$r = 4, -4$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 29
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