## Algebra 1

$y = 2x^{2} + 4x - 1$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= 2, b= 4, and c= -1 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(4)}{2(2)}$ $x= \frac{-4}{4}$ x=-1 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = 2x^{2} + 4x - 1$ $y = 2(-1)^{2} + 4(-1) - 1$ y= 2 - 4 - 1 y= -3 The vertex is (-1,-3)