## Algebra 1

$y = -3x^{2} + 12x + 1$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= -3, b= 12, and c= 1 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(12)}{2(-3)}$ $x= \frac{-12}{-6}$ x=2 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = -3x^{2} + 12x + 1$ $y = -3(2)^{2} + 12(2) + 1$ y= -12 + 24 + 1 y= 13 The vertex is (2,13)