Algebra 1

$y = -4x^{2} + 11$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= -4, b= 0, and c= 11 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(0)}{2(-4)}$ $x= \frac{0}{-8}$ x=0 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = -4x^{2} + 11$ $y = -4(0)^{2} + 11$ y= 0 + 11 y=11 The vertex is (0,11)