Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions\ - Practice and Problem-Solving Exercises: 14

Answer

Axis of symmetry: x=-2 Vertex: (-2,13)

Work Step by Step

$y = -4x^{2} - 16x - 3$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= -4, b= -16, and c= -2 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(-16)}{2(-4)}$ $x= \frac{16}{-8}$ x= -2 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = -4x^{2} - 16x - 3$ $y = -4(-2)^{2} - 16(-2) - 3$ y= -16 + 32 -3 y= 13 The vertex is (-2,13)
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