## Algebra 1

Published by Prentice Hall

# Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions\ - Practice and Problem-Solving Exercises: 13

#### Answer

Axis of symmetry: $x= \frac{3}{10}$ vertex: $(\frac{3}{10},\frac{49}{20})$

#### Work Step by Step

$y = -5x^{2} + 3x + 2$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= -5, b= 3, and c= 2 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(3)}{2(-5)}$ $x= \frac{3}{10}$ Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = -5x^{2} + 3x + 2$ $y = -5(\frac{3}{10})^{2} + 3(\frac{3}{10}) + 2$ $y= \frac{49}{20}$ The vertex is $(\frac{3}{10},\frac{49}{20})$

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