Algebra 1

$y = x^{2} - 8x - 7$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= 1, b= -8, and c= -7 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(-8)}{2(1)}$ $x= \frac{8}{2}$ x=4 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = x^{2} - 8x - 7$ $y = (4)^{2} - 8(4) - 7$ y= 16 - 32 - 7 y= -23 The vertex is (4,-23)