## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 9

#### Answer

$2z^{2}$ $and$ $3$

#### Work Step by Step

Given : $2z^{3}+$ $6z^{2}+$ $3z+$ $9$ After grouping, we get : $(2z^{3}+6z^{2})+(3z+9)$ This becomes : $2z^{2}(z+3)+3(z+3)$

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