Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 14

Answer

(7y + 4)($2y^{2} + 1$)

Work Step by Step

$14y^{3} + 8y^{2} + 7y + 4$ Factor by grouping, group the first two terms together. ($14y^{3} + 8y^{2} ) + (7y + 4$) Factor out the common factors from both parenthesis. $2y^{2}(7y + 4) + 1(7y + 4$) We take $(7y + 4$) and factor it out which gives us. (7y + 4)($2y^{2} + 1$)
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