Answer
$(3y+1)(4y^{2}-3)$
Work Step by Step
$12y^{3}=2.2.3.y.y.y$ and $4y^{2}=2.2.y.y$
Hence, $GCF=$$2.2.y.y=4y^{2}$
$9y=$$3.3.y$ and $3=3.1$
Hence, $GCF=3$
After grouping;
$=(12y^{3}+4y^{2})-(9y+3)$
$=4y^{2}(3y+1)-3(3y+1)$
$=(3y+1)(4y^{2}-3)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 519: 21
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
