Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 19

Answer

$(5v+6)(4v^{2}-5)$

Work Step by Step

$20v^{3}=$$2.2.5.v.v.v$ and $24v^{3}=$$2.2.2.3.v.v.v$ Hence , $GCF=2.2.v.v=4v^{2}$ $25v=5.5.v$ and $30=2.3.5$ Hence, $GCF=5$ After grouping : $=(20v^{3}+24v^{2})-(25v+30)$ $=4v^{2}(5v+6)-5(5v+6)$ $=(5v+6)(4v^{2}-5)$
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