Algebra 1

(2z - 5)($7z^{2}$ + 8)
$14z^{3} - 35z^{2} + 16z - 40$ Factor by grouping, group the first two terms together. $(14z^{3} - 35z^{2}) + (16z - 40)$ Factor out the common factors from both parenthesis. $7z^{2}$(2z - 5) + 8(2z - 5) We take (2z - 5) and factor it out which gives us. (2z - 5)($7z^{2}$ + 8)