## Algebra 1

$(11w-9)(w^{2}+1)$
$11w^{3}=$ $11.w.w.w$ and $9w^{2}=$ $3.3.w.w$ Here, $w^{2}$ is the largest term which you can factor out. Hence, $GCF=$$w^{2} Now, 11w=$$11.w$ and $9=3.3$ Hence, $GCF=1$ Then, after grouping : $=(11w^{3}-9w^{2})+(11w-9)$ $=w^{2}(11w-9)+ 1(11w-9)$ $=(11w-9)(w^{2}+1)$