Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 16

Answer

$(11w-9)(w^{2}+1)$

Work Step by Step

$11w^{3}=$ $11.w.w.w$ and $9w^{2}=$ $3.3.w.w$ Here, $w^{2}$ is the largest term which you can factor out. Hence, $GCF=$$w^{2}$ Now, $11w=$$11.w$ and $9=3.3$ Hence, $GCF=1$ Then, after grouping : $=(11w^{3}-9w^{2})+(11w-9)$ $=w^{2}(11w-9)+ 1(11w-9)$ $=(11w-9)(w^{2}+1)$
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