Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises: 49

Answer

$24 \sqrt 3 - 6 $

Work Step by Step

$\sqrt 12 + 4 \sqrt 75 - \sqrt 36 $ $\sqrt 12$ can be written as 4 x 3 because they are the factors of 12 $\sqrt 75$ can be written as 25 x 3 because they are the factors of 75 *** Square root of 36 is 6 because 6 x 6 = 36 $\sqrt (4 \times 3) + 4 \sqrt (25 \times 3) - 6 $ *** Square root of 4 is 2 because 2 x 2 =4 *** Square root of 25 is 5 because 5 x 5 = 25 $2 \sqrt ( 3) + 20 \sqrt (3) - 6 $ We see that it has the common factor of $\sqrt 3$ so we factor it out. $\sqrt 3 ( 2 + 22) - 6 $ $\sqrt 3 ( 24) - 6 $ $24 \sqrt 3 - 6 $
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