Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 617: 46

Answer

$3 \sqrt 6$

Work Step by Step

$\sqrt 6 + \sqrt 24$ $\sqrt 24$ can be written as 4 x 6 because they are the factors of 24 $\sqrt 6 + \sqrt (4 \times 6)$ We see that it has the common factor of $\sqrt 6$ so we factor it out. $\sqrt 6 ( 1 + \sqrt 4 )$ *** Square root of 4 is 2 because 2 x 2 =4 $\sqrt 6 ( 1 + 2)$ $\sqrt 6 (3)$ $3 \sqrt 6$
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