Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 617: 47

Answer

$5\sqrt 10$

Work Step by Step

Reduce the radicals by looking for perfect-square factors inside each of the radicals. $\sqrt 40$ + $\sqrt90$ = $\sqrt 4 * 10 + \sqrt 9 * 10$ $2\sqrt10$ + $3\sqrt10$ = $5\sqrt10$
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