## Algebra 1

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 617: 45

#### Answer

$3 \sqrt 3$

#### Work Step by Step

$\sqrt 3 + \sqrt 12$ $\sqrt 12$ can be written as 4 x 3 because they are the factors of 12 $\sqrt 3 + \sqrt (4 \times 3)$ We see that it has the common factor of $\sqrt 3$ so we factor it out. $\sqrt 3 ( 1 + \sqrt 4 )$ *** Square root of 4 is 2 because 2 x 2 =4 $\sqrt 3 ( 1 + 2)$ $\sqrt 3 (3)$ $3 \sqrt 3$

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