Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 617: 48

Answer

$6\sqrt2 + 6\sqrt3$

Work Step by Step

Multiply, then find perfect-square factors in each of the radicals. $3\sqrt2(2+\sqrt6)$= $6\sqrt2 + 3\sqrt12$ $6\sqrt2 + 3\sqrt4 *3$ = $6\sqrt2 + 6\sqrt3$
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