## Algebra 1

$x=6-4\sqrt{2}\approx0.3$
Rationalize the left side's denominator first by multiplying by its conjugate. $\frac{\sqrt{2}-1}{\sqrt{2}+1}\cdot \frac{\sqrt{2}-1}{\sqrt{2}-1}=\frac{x}{2}=\frac{2-2\sqrt{2}+1}{2-1}=3-2\sqrt{2}. x=6-4\sqrt{2}\approx0.3$