Answer
$x=3$ or $x=-\frac{1}{2}$
Work Step by Step
$2x^2-5x-3=0$
$2x^2-6x+x-3=0$
$2x(x-3)+(x-3)=0$
$(x-3)(2x+1)=0$
$x=3$ or $x=-\frac{1}{2}$
The equation has two solutions, $x=3$ or $x=-\frac{1}{2}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 20
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