Answer
The equation has two solutions, $r=\pm 6$.
Work Step by Step
$5r^2-180=0$
$r^2-36=0$
$(r-6)(r+6)=0$
$r=\pm 6$
The equation has two solutions, $r=\pm 6$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 15
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