Answer
The equation has two solutions, $n=\pm \frac{1}{2}$.
Work Step by Step
$36n^2=9$
$36n^2-9=0$
$4n^2-1=0$
$(2n-1)(2n+1)=0$
$n=\pm \frac{1}{2}$
The equation has two solutions, $n=\pm \frac{1}{2}$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 16
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