Answer
The equation has two solutions, $x= \pm 4$.
Work Step by Step
$x^2-16=0$
$(x-4)(x+4)=0$
$x=4$ or $x=-4$
The equation has two solutions, $x= \pm 4$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 10
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