Answer
$n=3$ or $n=-4$
Work Step by Step
$n^2+n-12=0$
$n^2-3n+4n-12=0$
$n(n-3)+4(n-3)=0$
$(n-3)(n+4)=0$
$n=3$ or $n=-4$
The equation has two solutions, $n=3$ or $n=-4$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 19
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