$b=1$ or $b=-4$
Work Step by Step
$b^2+3b-4=0$ $b^2-b+4b-4=0$ $b(b-1)+4(b-1)=0$ $(b-1)(b+4)=0$ $b=1$ or $b=-4$ The equation has two solutions, $b=1$ or $b=-4$
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