Answer
$(2v-1)(5v+8)$
Work Step by Step
$10v^{2}+11v-8=$
...find factors of $ac$ with a sum of $b$.
($ac=-80,\ b=11$)
$\left[\begin{array}{lll}
\text{Factors of -80} & \text{Sum of factors} & \\
1\text{ and }-80 & -79 & \\
-1\text{ and }80 & 79 & \\
2\text{ and }-40 & -42 & \\
-2\text{ and }40 & 38 & \\
4\text{ and }-20 & -16 & \\
-4\text{ and }20 & 16 & \\
5\text{ and }-16 & -11 & \\
-5\text{ and }16 & 11 & \text{ is what we need }
\end{array}\right]$
...use the factors you found to rewrite $bx$.
$=10v^{2}-5v+16v-8$
...factor by grouping.
$=5v(2v-1)+8(2v-1)$
...use the Distributive Property.
$=(2v-1)(5v+8)$
