# Chapter 8 - Polynomials and Factoring - Chapter Review - Page 537: 54

$-2(h-7)(h+5)$

#### Work Step by Step

$-2h^{2}+4h+70=$ ...factor out the GCF. $=-2(h^{2}-2h-35)$ ...find factors of $ac$ with a sum of $b$. ($ac=-35,\ b=-2$) $\left[\begin{array}{lll} \text{Factors of -35} & \text{Sum of factors} & \\ 1\text{ and }-35 & -34 & \\ -1\text{ and }35 & 34 & \\ 5\text{ and }-7 & -2 & \text{ is what we need } \end{array}\right]$ ...use the factors you found to rewrite $bx$. $=-2(h^{2}+5h-7h-35)$ ...factor by grouping. $=-2[h(h+5)-7(h+5)]$ ...factor again. $=-2(h-7)(h+5)$

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