#### Answer

$(n+2)(2n-1)$

#### Work Step by Step

$2n^{2}+3n-2=$
...find factors of $ac$ with a sum of $b$.
($ac=-4,\ b=3$)
$\left[\begin{array}{lll}
\text{Factors of -4} & \text{Sum of factors} & \\
1\text{ and }-4 & -3 & \\
-1\text{ and }4 & 3 & \text{ is what we need }
\end{array}\right]$
...use the factors you found to rewrite $bx$.
$=2n^{2}-n+4n-2$
...factor by grouping.
$=n(2n-1)+2(2n-1)$
...use the Distributive Property.
$=(n+2)(2n-1)$