## Algebra 1: Common Core (15th Edition)

$(3m+11n)(2m+n)$
$6m^{2}+25mn+11n^{2}=$ ...find factors of $ac$ with a sum of $b$. ($ac=66,\ b=25$) $\left[\begin{array}{lll} \text{Factors of 66} & \text{Sum of factors} & \\ 2\text{ and }33 & 35 & \\ 3\text{ and }22 & 25 & \text{ is what we need } \end{array}\right]$ ...use the factors you found to rewrite $bx$. $=6m^{2}+3mn+22mn+11n^{2}$ ...factor by grouping. $=3m(2m+n)+11n(2n+n)$ ...use the Distributive Property. $=(3m+11n)(2m+n)$