#### Answer

$21q^2 +62q+16$

#### Work Step by Step

To use the FOIL method, we multiply the first terms of each binomial, the first term of the first binomial and the last term of the second binomial, the last term of the first binomial and the first term of the second binomial, and the last terms of each binomial. We then find the sum of these products and combine the like terms to get our answer.
We apply this method to $(7q+2)(3q+8)$:$$(7q+2)(3q+8)=21q^2+6q+56q+16=21q^2+62q+16$$This answer is already in standard form because the exponents are in descending order.