Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 537: 44

Answer

$2(3k-2l)(k-l)$

Work Step by Step

$6k^{2}-10kl+4l^{2}=$ ...factor out the GCF. $=2(3k^{2}-5kl+2l^{2})$ ...find factors of $ac$ with a sum of $b$. ($ac=6,\ b=-5$) $\left[\begin{array}{lll} \text{Factors of 6} & \text{Sum of factors} & \\ -1\text{ and }-6 & -7 & \\ -2\text{ and }-3 & -5 & \text{ is what we need } \end{array}\right]$ ...use the factors you found to rewrite $bx$. $=2(3k^{2}-2kl-3kl+2l^{2}$ ...factor by grouping. $=2[k(3k-2l)-l(3k-l)]$ ...factor again. $=2(3k-2l)(k-l)$
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