Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 26



Work Step by Step

$3t^{4}=(3)\cdot t\cdot t\cdot t\cdot t$ $-6t^{3}=-1\cdot(3)\cdot 2\cdot t\cdot t\cdot t$ $-9t=-1\cdot(3)\cdot 3\cdot t$ $12=2\cdot 2\cdot(3)$ GCF=$3$ $3t^{4}-6t^{3}-9t+12=$ ...factor out the GCF $=3(t^{4})+3(-2t^{3})+3(-3t)+3(4)$ $...$apply the Distributive Property. $=3(t^{4}-2t^{3}-3t+4)$
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