## Algebra 1: Common Core (15th Edition)

$3(t^{4}-2t^{3}-3t+4)$
$3t^{4}=(3)\cdot t\cdot t\cdot t\cdot t$ $-6t^{3}=-1\cdot(3)\cdot 2\cdot t\cdot t\cdot t$ $-9t=-1\cdot(3)\cdot 3\cdot t$ $12=2\cdot 2\cdot(3)$ GCF=$3$ $3t^{4}-6t^{3}-9t+12=$ ...factor out the GCF $=3(t^{4})+3(-2t^{3})+3(-3t)+3(4)$ $...$apply the Distributive Property. $=3(t^{4}-2t^{3}-3t+4)$