Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 24



Work Step by Step

$45c^{3}=(3\cdot 3)\cdot 5\cdot(c)\cdot c\cdot c\cdot c\cdot c$ $-63c^{3}=-1\cdot(3\cdot 3)\cdot 7\cdot(c)\cdot c\cdot c$ $27c=(3\cdot 3)\cdot 3\cdot(c)$ GCF=$9c$ $45c^{5}-63c^{3}+27c$ $...$factor out the GCF $=9c(5c^{4})+9c(-7c^{2})+9c(3)$ $...$apply the Distributive Property. $=9c(5c^{4}-7c^{2}+3)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.