Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 27



Work Step by Step

$30h^{5}=2\cdot(3)\cdot 5\cdot h\cdot h\cdot[h\cdot h\cdot h]$ $-6h^{4}=-1\cdot 2\cdot(3)\cdot h\cdot[h\cdot h\cdot h]$ $-15h^{3}=-1\cdot(3)\cdot 5\cdot[h\cdot h\cdot h]$ GCF=$3h^{3}$ $30h^{5}-6h^{4} -15h^{3}$ ...factor out the GCF $=3h^{3}(10h^{2})+3h^{3}(-2h)+3h^{3}(-5) $ $...$apply the Distributive Property. $=3h^{3}(10h^{2}-2h-5)$
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