Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 23



Work Step by Step

$3b^{4}=(3\cdot b)\cdot b\cdot b\cdot b$ $-9b^{2}=-1\cdot 3\cdot(3\cdot b)\cdot b$ $6b=2\cdot(3\cdot b)$ GCF=$3b$ $3b^{4}-9b^{2}+6b$ $...$factor out the GCF $=3b(b^{3})+3b(-3b)+3b(2)$ $...$apply the Distributive Property. $=3b(b^{3}-3b+2)$
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