Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 22



Work Step by Step

$12p^{4}=(2\cdot 2\cdot p)\cdot p\cdot p\cdot p$ $16p^{3}=2\cdot 2\cdot(2\cdot 2\cdot p)\cdot p\cdot p$ $8p=2\cdot(2\cdot 2\cdot p)$ GCF=$4p$ $12p^{4}+16p^{3}+8p$ $...$factor out the GCF $=4p(3p^{3})+4p(4p^{2})+4p(2)$ $...$apply the Distributive Property. $=4p(3p^{3}+4p^{2}+2)$
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