Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 27

Answer

$p^{\frac{4}{3}}.q^{\frac{3}{2}}$

Work Step by Step

We are given: $(p^{\frac{1}{3}}q)(q^{\frac{1}{2}}p)$ $=p^{(\frac{1}{3}+1)}.q^{(1+\frac{1}{2})}$ $=p^{\frac{4}{3}}.q^{\frac{3}{2}}$

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