Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 14



Work Step by Step

You have $y^{-2}$$z^{2}$.Since $a^{-b}$=$\frac{1}{a^b}$ we have $\frac{z^2}{y^2}$ as the new expression..Plug in z=-5 and y=-3 in order to evaluate the expression: $\frac{(-5)^2}{(-3)^2}$ -evaluate exponents- =$\frac{25}{9}$
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