Algebra 1: Common Core (15th Edition)

You have the equation $x^{2}$ *$y^{5}$ $\times$$x^{m}*y^{n}=x^{5}*y^{11}.Solve for m and n: x^{2+m} \times y^{5+n}=x^{5}*y^{11} multiply the powers with the same base to add the exponents- 2+m=5 and 5+n=11 - solve both the equations individually- 2+m=5 -subtract 2 from both sides- m=3 5+n=11 - subtract 5 from both sides- n=6 M=3 and N=6 so the equation is x^{2} *y^{5} \times$$x^{3}$*$y^{6}$=$x^{5}$*$y^{11}$