## Algebra 1: Common Core (15th Edition)

We have $x^{0}$$y^{2}.We are given x=2 and y=-3 so we substitute them into the expression: 2^{0}$$(-3)^{2}$.Since any number raised to 0 is 1 we have 1$\times$$(-3)^{2}$ . -3 squared is 9 so we have 1$\times$9=9.The answer is 9