Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 10



Work Step by Step

We have $x^{0}$$y^{2}$.We are given x=2 and y=-3 so we substitute them into the expression: $2^{0}$$(-3)^{2}$.Since any number raised to 0 is 1 we have 1$\times$$(-3)^{2}$ . -3 squared is 9 so we have 1$\times$9=9.The answer is 9
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