Answer
$x^{\frac{2}{3}}.x^{\frac{1}{4}}=x^{\frac{11}{12}}$
Work Step by Step
$x^{\frac{2}{3}}.x^a=x^{\frac{11}{12}}$
$x^{\frac{2}{3}+a}=a^{\frac{11}{12}}$
Multiply the powers with the same base.
$\frac{2}{3}+a=\frac{11}{12}$
$a=\frac{1}{4}$
Therefore, the completed equation is:
$x^{\frac{2}{3}}.x^{\frac{1}{4}}=x^{\frac{11}{12}}$
