Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 475: 13



Work Step by Step

You are given:$\frac{5x^0}{y^-2}$.Plug in x=2 and y=-3 to evaluate the expression: $\frac{5(2^0)}{-3^-2}$ -any number raised to zero is always one.So $2^{0}$=1.Any number raised to a negative number becomes its opposite so $\frac{1}{-3^-2}$=$-3^{-2}$- So 5 $\times$ (-3$)^{2}$=5 $\times$9=45
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