#### Answer

45

#### Work Step by Step

You are given:$\frac{5x^0}{y^-2}$.Plug in x=2 and y=-3 to evaluate the expression:
$\frac{5(2^0)}{-3^-2}$ -any number raised to zero is always one.So $2^{0}$=1.Any number raised to a negative number becomes its opposite so $\frac{1}{-3^-2}$=$-3^{-2}$-
So 5 $\times$ (-3$)^{2}$=5 $\times$9=45