## Algebra 1: Common Core (15th Edition)

You are given:$\frac{5x^0}{y^-2}$.Plug in x=2 and y=-3 to evaluate the expression: $\frac{5(2^0)}{-3^-2}$ -any number raised to zero is always one.So $2^{0}$=1.Any number raised to a negative number becomes its opposite so $\frac{1}{-3^-2}$=$-3^{-2}$- So 5 $\times$ (-3$)^{2}$=5 $\times$9=45