Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 37



Work Step by Step

$\frac{2n^2-5n-3}{4n^2-12n-7}\div\frac{4n+5}{2n-7}$ $=\frac{2n^2-6n+n-3}{4n^2+2n-14n-7}\times\frac{2n-7}{4n+5}$ $=\frac{2n(n-3)+(n-3)}{2n(2n+1)-7(2n+1)}\times\frac{2n-7}{4n+5}$ $=\frac{(2n+1)(n-3)}{(2n+1)(2n-7)}\times\frac{2n-7}{4n+5}$ $=\frac{(n-3)(2n-7)}{(2n-7)(4n+5)}$ $=\frac{n-3}{4n+5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.