Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 47


$= \frac{2(3g+1)}{g(3g-1)}, with$ $g\ne\frac{1}{3}$

Work Step by Step

Given : $\frac{\frac{g+2}{3g-1}}{\frac{g^{2}+2g}{6g+2}}$ This becomes : $\frac{g+2}{3g-1} \times \frac{2\times(3g+1)}{g(g+2)}$ $= \frac{2(3g+1)}{g(3g-1)}$ (After dividing out the common factor (g+2))
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