Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 23



Work Step by Step

$\frac{4t+4}{t-3}\times(t^2-t-6)$ $=\frac{4(t+1)}{t-3}\times(t^2+2t-3t-6)$ $=\frac{4(t+1)}{t-3}\times[t(t+2)-3(t+2)]$ $=\frac{4(t+1)}{t-3}\times(t-3)(t+2)$ $=\frac{4(t+1)(t-3)(t+2)}{t-3}$ $=4(t+1)(t+2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.