Answer
$\frac{x-1}{x+3}, with$ $x\ne-3$
Work Step by Step
Given : $\frac{x-1}{x+4} \div \frac{x+3}{x+4}$
This becomes : $\frac{x-1}{x+4} \times \frac{x+4}{x+3}$
$= \frac{x-1}{x+3}$
(After dividing out the common factor $(x+4)$)
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