Answer
$3(m+2)(2m+1)$
Work Step by Step
$\frac{2m+1}{3m-6}\times(9m^2-36)$
$=\frac{2m+1}{3(m-2)}\times(3m-6)(3m+6)$
$=\frac{2m+1}{3(m-2)}\times3(m-2)\times3(m+2)$
$=\frac{(2m+1)\times3(m-2)\times3(m+2)}{3(m-2)}$
$=3(m+2)(2m+1)$
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