Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 27



Work Step by Step

$\frac{h-1}{6h+3}\times(2h^2+9h+4)$ $=\frac{h-1}{3(2h+1)}\times(2h^2+8h+h+4)$ $=\frac{h-1}{3(2h+1)}\times[2h(h+4)+(h+4)]$ $=\frac{h-1}{3(2h+1)}\times(2h+1)(h+4)$ $=\frac{(h-1)(2h+1)(h+4)}{3(2h+1)}$ $=\frac{(h-1)(h+4)}{3}$
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