Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 27

$\frac{(h-1)(h+4)}{3}$

$\frac{h-1}{6h+3}\times(2h^2+9h+4)$ $=\frac{h-1}{3(2h+1)}\times(2h^2+8h+h+4)$ $=\frac{h-1}{3(2h+1)}\times[2h(h+4)+(h+4)]$ $=\frac{h-1}{3(2h+1)}\times(2h+1)(h+4)$ $=\frac{(h-1)(2h+1)(h+4)}{3(2h+1)}$ $=\frac{(h-1)(h+4)}{3}$