## Algebra 1: Common Core (15th Edition)

The hypotenuse is 85 and one of the legs is 13. Find the other leg using $a^{2}$+$b^{2}$=$c^{2}$. Plug in the leg for A and the hypotenuse for B: $a^{2}$+$b^{2}$=$c^{2}$ $13^{2}$+$b^{2}$=$85^{2}$ -simplify the exponents- 169 + $b^{2}$=7225 -subtract 169 from both sides- $b^{2}$=7056 -find the square root of 7056 in order to solve for b- b=84 The other leg is 84.