## Algebra 1: Common Core (15th Edition)

The legs are 3.5 and 12. You have to find the hypotenuse using $a^{2}$+$b^{2}$=$c^{2}$. Plug in the legs for A and B: $a^{2}$+$b^{2}$=$c^{2}$ $3.5^{2}$+$12^{2}$=$c^{2}$ -simplify exponents- 156.25=$c^{2}$ -find the square root of 156.25 to solve for c- 12.5=c Thus, the hypotenuse is 12.5.